Remove filename from path

[monarch_dodra via Digitalmars-d-learn]

On Wednesday, 24 September 2014 at 17:15:39 UTC, Ali Çehreli 
wrote:
> find() and friends can be used:
>
> import std.algorithm;
>
> void main()
> {
>     string path = "myFile.doc";
>     string extension = ".doc";
>
>     path = findSplitBefore(path, extension)[0];
>     assert(path == "myFile");
> }

I had thought of that, but then you might get in trouble with 
something like:
string path = "myPath.doc.old"

> And three retro()s make one modern(): :p
>
> import std.algorithm;
> import std.range;
>
> void main()
> {
>     string path = "myFile.doc";
>     string extension = ".doc";
>
>     path = findSplitAfter(path.retro,
>                           extension.retro)
>            [1].retro;
>
>     assert(path == "myFile");
> }
>
> Ali

That was the next one I had. Except here:
- You still run into issues if the extension is *not* .doc (and 
there happens to be a .doc somewhere in there).
- You are paying for a search, when you are only interested in 
testing a prefix.

I had thought of this though:
void main()
{
     string path = "myFile.doc";
     string extension = ".doc";

     auto rpath = path.retro();
     skipOver(rpath, extension.retro);
     path = rpath.retro();
     assert(path == "myFile");
}

The "issue" though is that skipOver modifies an rvalue, so it's 
not as "functional-style" as I would have liked it.

Anyways, the conclusion here (IMO), is that to manipulate paths, 
use std.path.