Can I get caller name?

[Vladimir Panteleev via Digitalmars-d-learn]

On Friday, 26 September 2014 at 05:59:33 UTC, AsmMan wrote:
> for debugging purposes, I need to get the caller name. Is it 
> possible? if so, how do I do this?
>
> void foo()
> {
>   baa();
> }
>
> void baa()
> {
>   wrilten(caller_name()); // foo
> }
>
> I know I could create an extra parameter and pass the current 
> function name as argument but it isn't a possibility for now.

Method 1 (extra template parameter):

////////////// method1.d /////////////
import std.stdio;

void foo()
{
     baa();
}

void baa(string caller=__FUNCTION__)()
{
     writeln(caller);
}

void main()
{
     foo();
}
//////////////////////////////////////

Method 2 (slow, needs -g, also prints line number on Windows):

/////////////////////////// method2.d ///////////////////////////
import std.stdio;

void foo()
{
     baa();
}

void baa()
{
     writeln(getCaller());
}

void main()
{
     foo();
}

string getCaller()
{
     try
         throw new Exception(null);
     catch (Exception e)
     {
         import std.string, std.algorithm;
         string[] lines = e.toString().splitLines()[1..$];
         return lines.find!(line => line.canFind("getCaller"))[2];
     }
}
/////////////////////////////////////////////////////////////////