Possible to write a classic fizzbuzz example using a UFCS chain?

[wobbles via Digitalmars-d-learn]

On Tuesday, 28 April 2015 at 11:04:12 UTC, w0rp wrote:
> On Tuesday, 28 April 2015 at 10:46:54 UTC, Gary Willoughby 
> wrote:
>> After reading the following thread:
>>
>> http://forum.dlang.org/thread/nczgumcdfystcjqybtku@forum.dlang.org
>>
>> I wondered if it was possible to write a classic fizzbuzz[1] 
>> example using a UFCS chain? I've tried and failed.
>>
>> [1]: http://en.wikipedia.org/wiki/Fizz_buzz
>
> You can do this.
>
> import std.range : iota;
> import std.algorithm : map, each;
> import std.typecons : Tuple, tuple;
> import std.stdio : writeln;
>
> Tuple!(size_t, string) fizzbuzz(size_t number) {
>     if (number % 3 == 0) {
>         if (number % 5 == 0) {
>             return tuple(number, "fizzbuzz");
>         } else {
>             return tuple(number, "fizz");
>         }
>     } else if (number % 5 == 0) {
>         return tuple(number, "buzz");
>     }
>
>     return tuple(number, "");
> }
>
> void main(string[] argv) {
>     iota(1, 101)
>     .map!fizzbuzz
>     .each!(x => writeln(x[0], ": ", x[1]));
> }
>
> The desired output may vary, depending on variations of 
> FizzBuzz. (Some want the number always in the output, some 
> don't.) You could maybe do crazy ternary expressions instead of 
> writing a function, or put it directly in there as a lambda, 
> but both just look ugly, and you might as well just write a 
> function for it.

Crazy ternary experessions:

void main(){
         "%s".writefln(
                 iota(1, 100, 1)
                 .map!(a => a%3==0 ? (a%5==0? "fizzbuzz" : "fizz")
                     : a%5==0 ? "buzz" : a.to!string));
}