Shouldn't the pointers be different

[John Colvin via Digitalmars-d-learn]

On Wednesday, 7 January 2015 at 10:56:09 UTC, John Colvin wrote:
> On Wednesday, 7 January 2015 at 10:37:18 UTC, Nick wrote:
>> When i try to run the following code
>>
>> import std.stdio;
>>
>> void main(){
>> 	auto a= new test!int();
>>
>> 	a.add(0);
>> 	a.add(1);
>> }
>>
>> class test(T){
>>
>> 	void add(T e){
>> 		auto temp= new node();
>> 		writeln("new node", &temp);
>> 	}
>>
>> 	class node{
>> 		T v;
>> 	}
>> }
>> http://dpaste.dzfl.pl/c8e56b5954b8
>> The two nodes have the same address, is this right?
>
> I don't know the mechanism by which they are the same 
> (optimiser or garbage collector), but there's not reason why 
> they shouldn't be.
> By the time you get to the second `new node()` the first one is 
> completely unreachable, so why not just reuse the memory? 
> Considering you don't initialise them differently, the object 
> could even just be reused as-is.

Sorry, my mistake, bearophile is correct. Nonetheless, you 
shouldn't be surprised to see memory being re-used.