aa.byKeyValue().sort!"a.key < b.key"

[Nicholas Wilson via Digitalmars-d-learn]

On Saturday, 27 June 2015 at 12:27:59 UTC, H. S. Teoh wrote:
> On Sat, Jun 27, 2015 at 12:22:06PM +0000, Nicholas Wilson via 
> Digitalmars-d-learn wrote:
>> How do I iterate through an AA sorted by key?
>> 
>> I am unable to .dup the aa.byKeyValue().
>
> Because it is a range, not an array.
>
> To turn it into an array, write:
>
> 	aa.byKeyValue().array.sort!"a.key < b.key"
>
>
> T

Derp.

Thankyou!