std.random question
biozic via Digitalmars-d-learn
digitalmars-d-learn at puremagic.com
Sun May 3 03:10:33 PDT 2015
On Sunday, 3 May 2015 at 09:28:40 UTC, Dennis Ritchie wrote:
> On Sunday, 3 May 2015 at 09:04:07 UTC, tired_eyes wrote:
>> On Sunday, 3 May 2015 at 08:48:52 UTC, Dennis Ritchie wrote:
>>> On Sunday, 3 May 2015 at 08:42:57 UTC, tired_eyes wrote:
>>>> Feels pretty silly, but I can't compile this:
>>>>
>>>>
>>>> import std.random;
>>>> auto i = uniform(0, 10);
>>>>
>>>>
>>>> DMD spits this:
>>>>
>>>> /usr/include/dmd/phobos/std/random.d(1188): Error: static
>>>> variable initialized cannot be read at compile time
>>>> /usr/include/dmd/phobos/std/random.d(1231): called
>>>> from here: rndGen()
>>>> /usr/include/dmd/phobos/std/random.d(1231): called
>>>> from here: uniform(a, b, rndGen())
>>>>
>>>>
>>>> Perhaps I'm missing something obvious?
>>>> dmd 2.067.1, openSUSE 13.2 x64
>>>
>>> void main() {
>>> import std.random;
>>> auto i = uniform(0, 10);
>>> }
>>
>> Not so simple, unfortunately.
>> Actual code:
>>
>>
>> import std.random;
>>
>> struct Mystruct {
>> auto id = uniform(0, 10);
>> }
>>
>> void main() {
>> // wahtever
>> }
>>
>>
>> ..and no luck.
>
> I think it is a bug:
No. The aboc code defines a field of Mystruct calld 'id', with a
type inferred from the static initializer expression 'uniform(0,
10)'. The problem is that a static initializer is... static! So
the expression must be evaluated at compile-time. The uniform
generator from std.random cannot be used at compile-time, thus
the error.
You could do:
---
import std.random;
struct Mystruct {
int id;
static opCall() {
Mystruct s;
s.id = uniform(0, 10);
return s;
}
}
void main() {
auto s = Mystruct();
// whatever
}
---
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