Replacing nested loops foreach using map/each/etc

[anonymous via Digitalmars-d-learn]

On Monday, 25 May 2015 at 17:52:09 UTC, Dennis Ritchie wrote:
> But why is the solution breaks down when `s = 10000` ? :)
>
> import std.stdio, std.algorithm, std.range;
>
> int c;
> const x = 12, y = 65, z = 50, s = 100000;

Which is it, now? 4 or 5 zeros?

> void solve(Range)(Range r) {
> 	cartesianProduct(r, r, r).filter!(i => i[0] * (y + 3 * z) + 
> i[1] * (y + 2 * z) + i[2] * (y + z) == s).each!dout;
> }
>
> void main() {
>
>     auto a = iota(0, x + 1).array;
>
>     solve(a);
>
>     writefln(`%s total`, c);
> }
>
> void dout(Tuple)(Tuple idx) {
>     ++c;
> }
> -----
> http://rextester.com/XGDL26042

What do you mean it "breaks down"? Your original code doesn't 
print anything for s = 10_000 or s = 100_000, either.