Capturing __FILE__ and __LINE in a variadic templated function

[Nordlöw via Digitalmars-d-learn]

On Monday, 2 November 2015 at 09:54:50 UTC, John Colvin wrote:
> Works for me on multiple compilers. To be precise, this worked:
>
> template show(Args...)
> {
>     void show(string file = __FILE__, uint line = __LINE__, 
> string fun = __FUNCTION__)()
>     {
>         import std.stdio: write, writeln;
>         try
>         {
>             debug write(file, ":",line, ":" /* , ": in ",fun 
> */, " debug: ");
>             foreach (const i, Arg; Args)
>                 {
>                 if (i) debug write(", "); // separator
>                 debug write(Arg.stringof, " is ", Arg);
>             }
>             debug writeln();
>         }
>         catch (Exception) { }
>     }
> }
>
> unittest
> {
>     int x = 11;
>     show!x;
> }

No. This prints:

     Arg is 11

I want it to print the name of Arg in the closing as

     x is 11

equivalent to what my single-parameter overload

void show(alias arg, string file = __FILE__, uint line = 
__LINE__, string fun = __FUNCTION__)()
{
     import std.stdio: writeln;
     try
     {
         debug writeln(file, ":",line, ":" /* , ": in ",fun */, " 
debug: ", arg.stringof, " is ", arg);
     }
     catch (Exception) { }
}

does.