reading file byLine

[Jordan Wilson via Digitalmars-d-learn]

On Thursday, 3 September 2015 at 22:48:01 UTC, Jordan Wilson 
wrote:
> On Thursday, 3 September 2015 at 22:21:57 UTC, Namal wrote:
>>>
>>> ep18.d(10): Error: no property 'split' for type 'char[]'
>>> /usr/include/dmd/phobos/std/algorithm.d(427):        
>>> instantiated from here: MapResult!(__lambda1, ByLine!(char, 
>>> char))
>>> ep18.d(10):        instantiated from here: map!(ByLine!(char, 
>>> char))
>>>
>>> and then a long list to the end of my code
>>>  Error: undefined identifier a
>>
>> Hmm, seems I forgot to add std.string, now it works, but words 
>> seems not to be an array, at least I cannot access it like an 
>> array. words[0][0] leads to
>>
>>  Error: no [] operator overload for type MapResult!(__lambda1, 
>> ByLine!(char, char))
>>
>> So is is a map? How can I convert all the elements in it to 
>> integer and store it in a real array?
>
> I believe it's by using array:
> auto words = file.byLine()           // you've all lines in  
> range
>                   .map!(a => a.split).array();

Sorry, I didn't notice the "convert all the elements in it to 
integer" part.
I think I saw reference to the to! before...that is one way to 
convert.

auto words = file.byLine()           // you've all lines in range
                    .map!(a => a.split)
		   .map!(a => to!int(a)).array();