Is there a smart way to process a range of range by front ?
BBasile via Digitalmars-d-learn
digitalmars-d-learn at puremagic.com
Wed Sep 23 14:22:20 PDT 2015
On Wednesday, 23 September 2015 at 21:17:29 UTC, BBasile wrote:
> On Wednesday, 23 September 2015 at 21:04:44 UTC, Justin Whear
> wrote:
>> On Wed, 23 Sep 2015 20:48:03 +0000, BBasile wrote:
>>
>>> I was thinking to a general *interleave()* algorithm for any
>>> compatible Range of Range but I can't find any smart way to
>>> process each sub range by front
>>
>> Can you show a sample input and output to clarify what you
>> mean by interleave? It's possible that what you want is
>> std.range.frontTransversal, std.range.transversal, or
>> std.range.transposed.
>
> ---
> auto r0 = [[0,2],[1,3]];
> auto r1 = interleave(r0);
> assert(r1 = [0,1,2,3]);
> auto r2 = [[0,3],[1,4],[2,5]];
> auto r3 = interleave(r2);
> assert(r3 = [0,1,2,3,4,5]);
> ---
>
> the fact that the numbers are ordered is just an helper.
just imagine that there are double equal symbols in the
assertions...
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