How to allocate arrays of objects?

[Meta via Digitalmars-d-learn]

On Thursday, 11 February 2016 at 09:02:30 UTC, Jacob Carlborg 
wrote:
> On 2016-02-11 05:34, Adam D. Ruppe wrote:
>> On Thursday, 11 February 2016 at 04:31:12 UTC, cy wrote:
>>> as[0..$] = new A();
>>>
>>> before accessing .stuff on as[0].
>>
>> Loop through it and allocate each one rather than trying to do 
>> it in a
>> one liner like that.
>
> What about this?
>
> as[] = new A();
>
> Or will that allocate a new one for each element?

import std.stdio;

class Test
{
     int n;
     int m;
}

void main()
{
     auto testArr = new Test[](5);
     testArr[] = new Test();
     foreach (ref test; testArr)
     {
         writeln(cast(void*)test);
     }
}


Output:

2A41010
2A41010
2A41010
2A41010
2A41010


Not really surprising, I guess. You can always do `generate(() => 
new Test()).take(5).array`.