How to declare an alias to a function literal type

[ParticlePeter via Digitalmars-d-learn]

On Tuesday, 12 January 2016 at 16:22:48 UTC, ParticlePeter wrote:

> Actually, I do use only one param, and not int as well, hence I 
> would like the parameter list to be part of the alias.
> Your example works though.

This was confusing, lets start fresh:

I have a function "otherFunc" which takes a function with lots of 
parameters as argument:

void otherFunc( void function( ref int p1, float p2, ubyte p3, 
... ) mf );

Side-note, I use the keyword function to signal that it is a 
function and not a delegate, thought it is a delegate when not 
specified.

When I pass a parameter to otherFunc I use this syntax for an 
anonymous function parameter:

otherFunc( void function( ref int p1, float p2, ubyte p3 ) { 
myCode; } );

I would like to alias the function signature above:
alias MF = void function( ref int p1, float p2, ubyte p3 );

I can rewrite the definition of otherFunc like this:
void otherFunc( MF mf );

But I cannot pass an anonymous function to otherFunc like this:
otherFunc( MF { myCode; } );

Thats what I want. Any working example?


Ali, I do not pass an existing named function as a pointer. I am 
also not sure about the lambdas, as I do not return anything, I 
just want to process data, would that work?