Template specialization

[Marc Schütz via Digitalmars-d-learn]

On Friday, 22 January 2016 at 13:03:52 UTC, Darrell Gallion wrote:
> On Friday, 22 January 2016 at 11:23:56 UTC, Marc Schütz wrote:
>> On Friday, 22 January 2016 at 01:33:42 UTC, Darrell Gallion 
>> wrote:
>>> void foo(A)()
>>>         if (!is (A == int)) {
>>>     pragma(msg, "int");
>>> }
>>>
>>> void foo(A)()
>>>         if (is (A == int[])) {
>>>     pragma(msg, "int[]");
>>> }
>>>
>>> void main() {
>>>
>>>   foo!(int)();
>>>   foo!(int[])();
>>> }
>>>
>>> ===========
>>>
>>> source\app.d(15): Error: template app.foo cannot deduce 
>>> function from argument types !(int)(), candidates are:
>>> source\app.d(3):        app.foo(A)() if (!is(A == int))
>>> source\app.d(8):        app.foo(A)() if (is(A == int[]))
>>> source\app.d(16): Error: app.foo called with argument types 
>>> () matches both:
>>> source\app.d(3):     app.foo!(int[]).foo()
>>> and:
>>> source\app.d(8):     app.foo!(int[]).foo()
>>
>> Have a look at the first template constraint. It checks 
>> whether the template parameter _is not_ `int`, so of course, 
>> the first instantiation fails, and the second one is ambiguous.
>
> I'm aware this doesn't look right or compile.
> How do I do this?
>

Just remove the `!` in the first template constraint, and it will 
compile.

>
> void foo(int x)
> { }
>
> void foo(int [] x)
> { }
>
> template foo(T)(T x){}
>
> void main() {
>   int x;
>   int [] a;
>   foo((x);
>   foo(a);
>   foo("hi");
> }

You lost me here...