shuffle a character array
Mike Parker via Digitalmars-d-learn
digitalmars-d-learn at puremagic.com
Wed Jul 20 01:30:37 PDT 2016
On Wednesday, 20 July 2016 at 08:18:55 UTC, celavek wrote:
>
> As far as my current understanding goes the shuffle will be
> done in place.
> If I use the "representation" would that still hold, that is
> will I be able
> to use the same char[] but in the shuffled form? (of course I
> will test that)
representation does not allocate any new memory. It points to the
same memory, same data. If we think of D arrays as something like
this:
struct Array(T) {
size_t len;
T* ptr;
}
Then representation is doing this:
Array original;
Array representation(original.len, original.ptr);
So, yes, the char data will still be shuffled in place. All
you're doing is getting a ubyte view onto it so that it can be
treated as a range.
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