Behavior of __FILE__ in mixin template

Andre Pany via Digitalmars-d-learn digitalmars-d-learn at puremagic.com
Wed Jun 22 10:07:02 PDT 2016


Hi,

I thought a mixin template is copied into the place where the 
mixin statement
exists and then the coding is evaluated.
This seems not to be true for __FILE__

I have a module form, which has a class Form. This module also 
contains
following mixin template

mixin template formTemplate()
{
	void generateForm()
	{
		string getFormName(string file =  __FILE__)()
		{
			import std.string: indexOf;
			return file[0..file.indexOf(".")]~".frm";
		}

		enum fileContent = import(getFormName());
	}
}

In another module myform I have a class MyForm in which I call 
the mixin statement:
mixin formTemplate.

The purpose of the template coding is: The enum fileContent 
should contain
the text of a file, which has the same name as the module but the 
file ending .frm.

I tried different things, but either it doesn't compile or 
__FILE__ returns "form"
instead of "myform".

Is this behavior correct? Do you have any tip?

Kind regards
André





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