Real implicitly converts to float?

[Tofu Ninja via Digitalmars-d-learn]

On Thursday, 23 June 2016 at 13:57:57 UTC, Steven Schveighoffer 
wrote:
> Whenever you work with floating point, the loss of precision 
> must be expected -- a finite type cannot represent an infinite 
> precision number.

The loss in precision should still be a warning. If I am using 
reals then I obviously needed a certain level of precision, I 
don't want to accidentally lose that precision somewhere because 
the compiler decided it was not important enough to warn me about 
it.