Concatenate 2 ranges
Vladimir Panteleev via Digitalmars-d-learn
digitalmars-d-learn at puremagic.com
Fri Nov 11 05:33:20 PST 2016
On Friday, 11 November 2016 at 13:30:17 UTC, RazvanN wrote:
> I know that I can use the .array property, but I think that
> this iterates through all of my elements. Using
> assumeSorted(chain(r1, r2).array) will return a SortedRange,
> but I am not sure what the complexity for this operation is.
.array allocates, so it's going to be O(n), but the allocation
will probably be more expensive.
> Is there a way to concatenate 2 ranges (SortedRange in my case)
> in O(1) time?
assumeSorted(chain(a, b)) ?
This works for me:
auto r = assumeSorted(chain([1, 2, 3].sort(), [1, 2, 3].sort()));
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