The return of std.algorithm.find
RazvanN via Digitalmars-d-learn
digitalmars-d-learn at puremagic.com
Tue Nov 15 01:50:40 PST 2016
On Tuesday, 15 November 2016 at 09:43:27 UTC, RazvanN wrote:
> The find function which receives an input haystack and a needle
> returns the haystack advanced to the first occurrence of the
> needle. For normal ranges this is fine, but for
> sorted ranges (aka SortedRange) it is a bit odd. For example:
>
> find(assumeSorted[1, 2, 4, 5, 6, 7], 4) would return [4, 5, 6,
> 7]. This is in terms with the general policy of the find
> function, but is weird. Since we know the range is sorted,
> shouldn't the result be [1, 2, 4]?
The whole function is find!"a <= b"(assumeSorted([1, 2, 4, 5, 6,
7]), 4). And the result is
the whole range [1, 2, 4, 5, 6, 7].
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