cannot deduce template lambda from argument

[Biotronic]

On Tuesday, 5 December 2017 at 23:01:43 UTC, aliak wrote:
> immutable lambda(T) = (T n) => n * n;

Generally, you'd want to write

     alias lambda = n => n * n;

instead. That said, I don't see any reason why your syntax 
shouldn't work, and would argue it's a bug. Please file it in 
Bugzilla.

--
   Biotronic