Sort in return statement

[user1234]

On Saturday, 9 December 2017 at 03:24:52 UTC, codephantom wrote:
> On Saturday, 9 December 2017 at 02:45:35 UTC, rjframe wrote:
>>
>> `sort` returns a SortedRange of ushorts, not an array of 
>> ushorts. Make it:
>>
>> ```
>> import std.array : array;
>> return sort(numbers.take(8)).array;
>> ```
>>
>> --Ryan
>
> That's it!
>
> Thanks Ryan.

You can also return a lazy range:

```
auto draw8Numbers()
{
      import std.meta : aliasSeqOf;
      import std.range : iota, take;
      ushort[] numbers = [ aliasSeqOf!(iota(1,46)) ];
      import std.random : randomShuffle;
      randomShuffle(numbers);
      import std.algorithm.sorting : sort;
      return sort(numbers[].take(8));
}

void main()
{
     import std.array;
     ushort[] nbrs = draw8Numbers.array; // evaluated after 
return, during assingment
}
```