How to catch line number of exception without catching it ?

[Thomas]

Hi forks!

I wanted to ask if there is a way to catch the line position on 
an exception without setting a try + catch block ?
What I want is something like this:


module main;

import std.stdio;
import std.conv;

void foo()
{
	scope(failure)
	{
		writeln("Got a failure in ", __FILE__, " ", __FUNCTION__, "!" );
		// what I miss is the line position with __LINE__
	}
	
	int x = to!int("1x");  // <-- here is the exception throwing

}

int main()
{
	foo();
	return 0;
}


My goal is to trace the failure from the branch back to the root 
like this:

(error) in "module2" at "foo2()" on line "..."
(error) in "module1" at "foo1()" on line "..."
(error) in "main" at "main()" on line "..."

I don't want to set on every function a try + catch functionality 
because I think it is not a good coding style. Also I dont want 
to send on every possible position where an exception/error could 
happen (even when catched) the line position into an error log 
function. So I got the idea of writing out modulename and 
function with scope(failure) on the beginning of each function, 
which works great recursive, but only the line position is 
missing.
So my question is: Is there a way to catch that line where the 
exception has happened without a catch ?

Or is there a better solution for tracing the error position from 
root till the branch ?

Thank you for your time!