std way to remove multiple indices from an array at once

[Seb]

On Wednesday, 20 December 2017 at 23:01:17 UTC, aliak wrote:
> Hi, is there a way to remove a number of elements from an array 
> by a range of indices in the standard library somewhere?
>
> I wrote one (code below), but I'm wondering if there's a better 
> way?
>
> Also, can the below be made more efficient?
>
> auto without(T, R)(T[] array, R indices) if (isForwardRange!R 
> && isIntegral!(ElementType!R) && !isInfinite!R) {
>     T[] newArray;
>     ElementType!R start = 0;
>     foreach (i; indices) {
>         newArray ~= array[start .. i];
>         start = i + 1;
>     }
>     newArray ~= array[start .. $];
>     return newArray;
> }
>
> // Usage
> long[] aa = [1, 2, 3, 4]
> aa = aa.without([1, 3])
>
> Thanks!

Try std.algorithm.mutation.remove [1]:

```
import std.algorithm, std.range, std.stdio, std.typecons;
auto r = 10.iota.array;
r.remove(tuple(2, 4)).writeln;
```

Play with it: https://run.dlang.io/is/RcL3VX

[1] https://dlang.org/phobos/std_algorithm_mutation.html#remove