Pass type directly to a template function?

[Mike Parker via Digitalmars-d-learn]

On Tuesday, 7 February 2017 at 21:40:04 UTC, Dukc wrote:
> On Tuesday, 7 February 2017 at 10:21:20 UTC, Mike Parker wrote:
>>>     function2!float(); //?
>>>     function3!float(); //?
>>
>> Yes, this is how it's done.
>
> Not quite with function3, because it takes one unnamed runtime 
> parameter. It can be called like function1 however. The value 
> of the parameter does not matter because it's unused, only the 
> type.

Yes, I missed the runtime parameter.