Convert call to a string

[H. S. Teoh via Digitalmars-d-learn]

On Wed, Feb 15, 2017 at 10:58:42PM +0000, ag0aep6g via Digitalmars-d-learn wrote:
> On Wednesday, 15 February 2017 at 22:34:22 UTC, H. S. Teoh wrote:
> > 	auto debugPrint(alias fun, A...)(A args) {
> > 		writefln("%s(%(%s, %))", __traits(identifier, fun), [args]);
> > 		return fun(args);
> > 	}
> > 
> > 	string arg = "hello";
> > 	string myCall = debugPrint!someFunction(1, arg);
> 
> `[args]` doesn't work when the tuple elements don't have a common
> type.

Very good point.


> But you can pass `args` as is to writefln and generate the format
> string accordingly:
> 
> ----
> import std.range: repeat;
> import std.string: join;
> 
> immutable string argsfmt = "%s".repeat(args.length).join(", ");
> writefln("%s(" ~  argsfmt ~ ")", __traits(identifier, fun), args);
> ----

Excellent idea!


T

-- 
Life is complex. It consists of real and imaginary parts. -- YHL