Convert duration to years?

[rikki cattermole via Digitalmars-d-learn]

On 15/01/2017 9:40 PM, Nestor wrote:
> I cleaned up the function a little, but it still feels like a hack:
>
> uint getAge(uint yyyy, uint mm, uint dd) {
>   import std.datetime;
>   SysTime t = Clock.currTime;
>   ubyte correction = 0;
>   if(
>     (t.month < mm) ||
>     ( (t.month == mm) && (t.day < dd) )
>   ) correction += 1;
>   return (t.year - yyyy - correction);
> }
>
> Isn't there anything better?

The problem with this is that it won't take into account leap years.