Convert duration to years?

[Nestor via Digitalmars-d-learn]

On Sunday, 15 January 2017 at 11:01:28 UTC, biozic wrote:
> On Sunday, 15 January 2017 at 08:40:37 UTC, Nestor wrote:
>> I cleaned up the function a little, but it still feels like a 
>> hack:
>>
>> uint getAge(uint yyyy, uint mm, uint dd) {
>>   import std.datetime;
>>   SysTime t = Clock.currTime;
>>   ubyte correction = 0;
>>   if(
>>     (t.month < mm) ||
>>     ( (t.month == mm) && (t.day < dd) )
>>   ) correction += 1;
>>   return (t.year - yyyy - correction);
>> }
>>
>> Isn't there anything better?
>
> It doesn't feel like a hack to me, because it's simple and 
> correct code that comply with the common definition of a 
> person's age. The only inaccuracy I can think of is about 
> people born on February 29th...

I know. I thought about it as well, but it's not something you 
can deal with cleanly.

For example, take a baby born in february 29 of year 2000 (leap 
year). In february 28 of 2001 that baby was one day short to one 
year.

Family can make a concession and celebrate birthdays in february 
28 of non-leap years, but march 1 is the actual day when the year 
of life completes. Which one to choose?

Another way to deal with this is modifying the function to take a 
parameter which allows to do a relaxed calculation in non-leap 
years if one so desires.