Overloading funtion templates.

[vit via Digitalmars-d-learn]

On Wednesday, 28 June 2017 at 11:49:57 UTC, Balagopal Komarath 
wrote:
> Shouldn't the compiler be able to resolve foo!g(3) to the first 
> template foo?
>
> import std.stdio;
> import std.algorithm;
> import std.range;
>
> auto foo(F, T)(T x)
> {
>     return x.foo(F);
> }
>
> auto foo(F, T)(T x, F f)
> {
>     return f(x);
> }
>
> int g(int x) { return x; }
>
> void main()
> {
>     foo(3, &g); // 2nd foo
>     foo!g(3);   // error
> }
>
> I get the error message.
>
> onlineapp.d(20): Error: template onlineapp.foo cannot deduce 
> function from argument types !(g)(int), candidates are:
> onlineapp.d(5):         onlineapp.foo(F, T)(T x)
> onlineapp.d(10):        onlineapp.foo(F, T)(T x, F f)

symbol 'g' isn't type.

auto foo(alias F, T)(T x)
{
     return x.foo(&F);
}