convert string to ubyte[]

[Guillaume Piolat]

On Saturday, 11 November 2017 at 15:38:18 UTC, aki wrote:
> Hello,
>
> This will be trivial question but I cannot figure out
> what's wrong. I want to convert string to an array of ubyte.
>
> import std.conv;
> void main() {
>         auto s = "hello";
>         ubyte[] b = to!(ubyte[])(s);
> }
>
> It compiles but cause run time error:
>
> std.conv.ConvException at C:\APP\D\dmd2\windows\bin\..\..\src\phobos\std\conv.d(3530): Can't parse string: "[" is missing
>
> I cannot understand the meaning of this message.
> Replacing s with s.dup to remove immutable doesn't help.
> Do I need to use cast?
>
> Regards,
> Aki

to!(ubyte[]) is a semantic transformation that tries to parse an 
array literal it seems.

You can use slice casting instead:

      import std.conv;
      void main() {
           auto s = "hello";
           ubyte[] b = cast(ubyte[])(s.dup);
      }