minElement on array of const objects
Temtaime
temtaime at gmail.com
Mon Nov 13 10:31:52 UTC 2017
On Monday, 13 November 2017 at 10:20:51 UTC, Aurelien Fredouelle
wrote:
> Hi all,
>
> It seems that it is not possible to use minElement on an array
> of const objects:
>
> class A
> {
> int val;
> }
>
> const(A) doStuff(const(A)[] v)
> {
> import std.algorithm.searching : minElement;
> return v.minElement!"a.val";
> }
>
> This gets the following compiler error:
>
> std/algorithm/searching.d(1256,28): Error: cannot implicitly
> convert expression (front(r)) of type const(A) to app.A
> std/algorithm/searching.d(1286,35): Error: cannot implicitly
> convert expression (r[i]) of type const(A) to app.A
> std/algorithm/searching.d(1258,36): Error: template instance
> std.algorithm.searching.extremum!("a.val", "a < b", const(A)[],
> A) error instantiating
> std/algorithm/searching.d(3345,24): instantiated from
> here: extremum!("a.val", "a < b", const(A)[])
> source/app.d(11,11): instantiated from here:
> minElement!("a.val", const(A)[])
>
> Is there a reason why this is not allowed? Shouldn't minElement
> be able to return a const(A) in this situation?
>
> Thanks,
> Aurelien
It should not until it uses recursion to find min element.
const(Class) res = ...;
...
return res;
Algorithm tries to assign to res variable and fails because in D
const(Class) means both const object and const reference to it.
So we cannot assign another reference to const(Class) variable.
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