How to imporve D-translation of these Python list comprehensions ?

[Ola Fosheim Grøstad]

On Thursday, 1 February 2018 at 20:18:37 UTC, Ola Fosheim Grøstad 
wrote:
> On Monday, 15 January 2018 at 19:05:52 UTC, xenon325 wrote:
>>     def aget(d, k1, k2):
>>         return d.get(k1, {}).get(k2, '')
>>
>>     aa = ['ver', 'rev']
>>     kk = set(chain(srv1.keys(), srv2.keys()))
>>     dd = [dict(_name=k, **{a + str(i): aget(d, k, a) for a in 
>> aa for i, d in enumerate([srv1, srv2])}) for k in sorted(kk)]
>
> But that was really verbose, why didn't he contract everything 
> into one line?
>
> dd = [dict(_name=k, **{a + str(i): d.get(k,{}).get(a,'') for a 
> in ('ver','rev') for i, d in enumerate((srv1, srv2))}) for k in 
> sorted(set(chain(srv1.keys(), srv2.keys())))]
>
> :*)

Rewritten in without comprehensions it is something like:

dd = []
for k in sorted(set(chain(srv1.keys(), srv2.keys()))):
      record = {'_name':k}
      for a in 'ver','rev':
            for i, d in enumerate((srv1, srv2)):
                record[f'{a}{i}'] = d.get(k,{}).get(a,'')
      dd.append(record)