more OO way to do hex string to bytes conversion
Machin
machgyl at zbor.ue
Tue Feb 6 18:59:30 UTC 2018
On Tuesday, 6 February 2018 at 18:33:02 UTC, Ralph Doncaster
wrote:
> I've been reading std.conv and std.range, trying to figure out
> a high-level way of converting a hex string to bytes. The only
> way I've been able to do it is through pointer access:
>
> import std.stdio;
> import std.string;
> import std.conv;
>
> void main()
> {
> immutable char* hex = "deadbeef".toStringz;
> for (auto i=0; hex[i]; i += 2)
> writeln(to!byte(hex[i]));
> }
>
>
> While it works, I'm wondering if there is a more
> object-oriented way of doing it in D.
converting data has nothing to do with OOP.
In D we write like that:
```
import std.range : chunks; // consumes lazily two by
two
import std.algorithm.iteration : map; // apply a func to the
chuncks
import std.conv : to; // the func: convert with
a custom base
import std.array : array; // render the whole stuff
ubyte[] a = "deadbeef".chunks(2).map!(a => a.to!ubyte(16)).array;
```
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