free func "front" is not picked up as a candidate when doing range.front(...)

[Paul Backus]

On Wednesday, 7 February 2018 at 19:25:01 UTC, aliak wrote:
>     import std.range: iota;
>     0.iota.front(100).writeln;
> // Error: inout method std.range.iota!(int, 
> int).iota.Result.front is not callable using a mutable object
>
>     import std.algorithm: filter;
>     auto arr = [0, 1];
>     arr.filter!"true".front(99).writeln;
> // Error: function 
> std.algorithm.iteration.FilterResult!(unaryFun, 
> int[]).FilterResult.front () is not callable using argument 
> types (int)
>

You can only call a function with UFCS syntax if the object 
you're calling it with does not have a member with the same name 
as the function. Both iota's `Result` type and `FilterResult` 
have properties named "front", so you can't call your front 
function on them using UFCS syntax.