iota to array

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On Sunday, 25 February 2018 at 06:22:03 UTC, psychoticRabbit 
wrote:
> On Sunday, 25 February 2018 at 05:40:19 UTC, Jonathan M Davis 
> wrote:
>>
>>     int[] intArr = iota(1, 11).array();
>>
>>
>> - Jonathan M Davis
>
> thanks!
>
> oh man.  It's so easy to do stuff in D ;-)
>
> But this leads me to a new problem now.
>
> When I run my code below, I get ints printed instead of 
> doubles??
>
> ---------------------
> module test;
>
> import std.stdio : writeln;
> import std.traits : isArray;
> import std.array : array;
> import std.range : iota;
>
>
> void main()
> {
>     int[] intArr = iota(1, 11).array(); // 1..10
>     double[] doubleArr = iota(1.0, 11.0).array(); // 1.0..10.0
>     char[] charArr = iota('a', '{').array();  // a..z
>
>     printArray(intArr);
>     printArray(doubleArr); // why is it printing ints instead 
> of doubles??
>     printArray(charArr);
> }
>
> void printArray(T)(const ref T[] a) if (isArray!(T[]))
> {
>     foreach(t; a)
>         writeln(t);
> }
>
> ---------------------------------

2 Things:
1. You can just use writeln to directly print Arrays. If you want 
a specific format for the array you can use writef/writefln
2. By default, writeln will print [1, 2, 3] when your array 
contains [1.0, 2.0, 3.0], since thats considered neater. You can 
use writefln to address that. You can see this here: 
https://run.dlang.io/is/bNxIsH

You can read more about format strings here:
https://dlang.org/phobos/std_format.html#format-string