iota to array

[psychoticRabbit]

On Sunday, 25 February 2018 at 06:35:07 UTC, Jonathan M Davis 
wrote:
>
> It's not printing ints. It's printing doubles. It's just that 
> all of the doubles have nothing to the right of the decimal 
> point, so they don't get printed with a decimal point. If you 
> did something like start with 1.1, then you'd see decimal 
> points, because there would be data to the right of the decimal 
> point. The same thing happens if you do
>
> writeln(1.0);
>
> as opposed to something like
>
> writeln(1.3);
>

thanks.

But umm.... what happended to the principle of least astonishment?

writeln(1.1); (prints 1.1)
whereas..
writeln(1.0); (prints 1)

I don't get it. Cause it's 'nicer'??

I ended up having to work around this..like this:

-------
void printArray(T)(const ref T[] a) if (isArray!(T[]))
{
     if( isFloatingPoint!T)
         foreach(t; a) writefln("%.1f", t);
     else
         foreach(t; a) writefln("%s", t);

}
-------