Zip with range of ranges
Paul Backus
snarwin at gmail.com
Sun Feb 25 20:18:27 UTC 2018
On Sunday, 25 February 2018 at 16:22:19 UTC, ARaspiK wrote:
> Instead of passing std.range.zip a set of ranges as different
> arguments, is it possible to hand the m a range of ranges, and
> get them to zip together each element of every subrange?
`std.range.transposed` does this, but it requires that the range
of ranges has assignable elements, so it may not work in all
cases. For example:
import std.range;
import std.algorithm.iteration;
import std.stdio;
auto rr1 = [[1, 2, 3], [4, 5, 6]];
rr1.transposed.each!writeln; // Works
auto rr2 = only(only(1, 2, 3), only(4, 5, 6));
rr2.transposed.each!writeln; // Doesn't work
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