Passing function(whose parameter would be dynamic and the type is unknown) as a parameter to another function.

[vino.B]

On Sunday, 8 July 2018 at 19:10:24 UTC, Alex wrote:
> On Sunday, 8 July 2018 at 18:46:31 UTC, vino.B wrote:
>>  Request you help, in the below code we pass the function 
>> "Testfun" as a parameter to another function "process" in 
>> order for the function "process" to work we have to specify 
>> the type of the parameter that is passed to the function "(T 
>> function(string, int) coRoutine, string Test, int Size) ", so 
>> now how do we pass a function whose parameter would be dynamic 
>> and the type is unknown.
>
> What do you mean with a "function with dynamic parameters" and 
> "unknown type"?
>
> But how about
>
> ´´´
> void main()
> {
> 	process!fun();
> }
>
> void process(alias coRoutine, T...)(T params)
> {
> 	coRoutine(params);
> }
>
> auto fun(T...)(T params)
> {
>
> }
> ´´´

HI Alex,

  I tried you method, but it not working as expected, the 
process!fun1(Test1) works but the process!fun2(Test1, Size ) does 
not work, instead of displaying the value (Test, 1) it output's 
the parameter "Test1".

Output:
Test
Test1

If I comment process!fun1(Test1); then the output is same

Output :
Test1

import std.stdio: writeln;


void main()
{
     string Test1 = "Test";
     int Size = 1;
     process!fun1(Test1);
     process!fun2(Test1, Size );
}

void process(alias coRoutine, T...)(T params)
{
	coRoutine(params);
}

auto fun1(T...)(T params)
{
    writeln(params);
}

auto fun2(T...)(T params)
{
    writeln(params);
}

From,
Vino.B