Inconsistent behavior of __FILE__ within mixin template

[Exil]

On Wednesday, 29 May 2019 at 08:45:45 UTC, Andre Pany wrote:
> Hi,
>
> I have a module a.d
>
> ---------------
> struct TestClass
> {
>     string name;
>     string fileName;
> }
>
> TestClass[] testClasses;
>
> mixin template UnitTest()
> {
>     private static string getFileName(string fileName = 
> __FILE__)
>     {
>         return fileName;
>     }
>
>     private static this()
>     {
>         testClasses ~= TestClass(this.classinfo.name, 
> getFileName());
>     }
> }
>
> and a module b.d
> ---------------
> import std.stdio;
> import a;
>
> class MyTest
> {
>     mixin UnitTest;
>
>     this()
>     {
>         writeln(getFileName());
>     }
> }
>
> void main()
> {
>     new MyTest();
>     writeln(testClasses);
> }
>
> What I want is to have in the struct array testClasses the file 
> name of module b
> to generate an xml report. But the output of this application is
>
>> b.d
>> [TestClass("b.MyTest", "a.d")]
>
> I would have thought __FILE evaluates in both cases to "b.d" as 
> the code is mixed into
> module b. Is this the intended behavior?
>
> Kind regards
> André

I imagine __FILE__ is used where the code is defined, since it is 
defined in "a.d" that is what is used. If you want to know the 
file name of where it is used then you can add it as part of the 
template.

mixin template UnitTest(string filename = __FILE__)
{
     private static this()
     {
         testClasses ~= TestClass(this.classinfo.name, filename );
     }
}