@safe function with __gshared as default parameter value
john.michael.hall at gmail.com
Wed Apr 8 19:22:11 UTC 2020
On Wednesday, 8 April 2020 at 18:50:16 UTC, data pulverizer wrote:
> On Wednesday, 8 April 2020 at 16:53:05 UTC, Anonymouse wrote:
>> import std.stdio;
>> __gshared int gshared = 42;
>> void foo(int i = gshared)
>> void main()
>> This currently works; `foo` is `@safe` and prints the value of
>> `gshared`. Changing the call in main to `foo(gshared)` errors.
>> Should it work, and can I expect it to keep working?
> According to the manual it shouldn't work at all
> https://dlang.org/spec/function.html#function-safety where it
> says Safe Functions: "Cannot access __gshared variables.", I
> don't know why calling as `foo()` works.
You still wouldn't be able to manipulate gshared within the
function. Though it may still be a problem for @safe...
__gshared int gshared = 42;
@safe void foo(int i = gshared)
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