How do you peek a variant containing a complex value?

[nullptr]

On Saturday, 22 February 2020 at 18:00:16 UTC, Vinay Sajip wrote:
> The following program won't compile if I uncomment the if 
> statement:
>
> void main()
> {
>     Variant v = complex(1.0, 1.0);
>
> //    if (v.peek!(Complex)) {
> //        writeln("Complex");
> //    }
>     writeln(v);
> }
>
> I get the same error with v.peek!(complex), which is:
>
> Error: template instance peek!(Complex) does not match template 
> declaration peek(T)()
>
> The variant can clearly hold a complex value. Someone please 
> tell me - what am I doing wrong in the peek call?

The type in v isn't Complex, it's Complex!double.

This will work the way you want:
```
void main()
{
     Variant v = complex(1.0, 1.0);

     if (v.peek!(Complex!double))
     {
         writeln("Complex");
     }

     writeln(v);
}
```