Aliasing current function template instance

[Jean-Louis Leroy]

Is it possible, inside a function template, to create an alias to 
the instantiated function? IOW the equivalent of __FUNCTION__, 
but yielding an alias?

The closest I came is:

   import std.string;
   import std.traits;

   void foo(T)(lazy T)
   {
     mixin(
       "alias thisFunction = ",
       __FUNCTION__[0..__FUNCTION__.lastIndexOf('.')],
       ";");
     pragma(msg, Parameters!thisFunction);
   }

   void main()
   {
     foo(0);
     foo("");
   }

   dmd -c aliasthisfunction.d
   (lazy int)
   (lazy string)

...but (unsurprisingly) this fails in presence of overloads. I.e. 
if I throw in:

   void foo(T)(int, T);

...then I get:

   aliasthisfunction.d(6): Error: template `aliasthisfunction.foo` 
matches more than one template declaration:
   aliasthisfunction.d(4):     `foo(T)(lazy T)`
   and
   aliasthisfunction.d(20):     `foo(T)(int, T)`
   ...

Something I have overlooked? Any ideas?