Asserting that a base constructor is always called

[Tim]

On Saturday, 23 May 2020 at 22:15:49 UTC, Ali Çehreli wrote:
> Is it not already called? I tried the following and it seems to 
> work:
>
> import std.stdio;
>
> GameObject[1] world;
> enum layer = 0;
>
> /// Base class of most objects in the game
> class GameObject{
>   this(){
>     world[layer] = this;
>     writeln("called");
>   }
>
>   abstract void update(){}
>
>   void draw(){}
> }
>
> class A : GameObject {
>   this(int i) {
>     writeln(__FUNCTION__);
>   }
>
>   override void update() {
>   }
> }
>
> void main() {
>   auto a = new A(42);
> }
>
> Ali

It is but I want to make sure for other cases in the future where 
I create a new class that inherits from GameObject. This was I 
can avoid future bugs by ensure that all classes in the future 
that inherit from GameObject, call it's constructor