Asserting that a base constructor is always called

[Nicholas Wilson]

On Sunday, 24 May 2020 at 06:38:46 UTC, Tim wrote:
> Oh right. I mean it makes sense but I got confused when super() 
> is valid syntax. Why would you need to call the super 
> constructor when it's called automatically?

A base class with a constructor that has no args will 
automatically get called at the start of a child class if it is 
not explicitly called. You can call it yourself anywhere in an 
always executed branch of the constructor. As for why, if you 
wanted to do some logging before the base constructor was called.

You need to call the base class's constructor explicitly when it 
has arguments and there is no default constructor in the base 
class. This must be done in an always executed branch. This must 
be called or the compiler will issue an error.