A function to split a range into several ranges of different chunks

[Seb]

On Monday, 14 September 2020 at 07:49:31 UTC, Andrej Mitrovic 
wrote:
> -----
> import std.range;
> import std.stdio;
>
> void main ()
> {
>     auto range = sequence!((a, n) => n);
>
>     // works, but the chunks are all the same length
>     auto rngs = range.chunks(4);
>     writeln(rngs[0]);
>     writeln(rngs[1]);
>     writeln(rngs[2]);
>
>     // want this
>     auto ranges = range.???(3, 4, 5);
>     writeln(ranges[0] == [1, 2, 3]);
>     writeln(ranges[1] == [4, 5, 6, 7]);
>     writeln(ranges[2] == [8, 9, 10, 11, 12]);
> }
> -----
>
> Do you know of a simple way to do this? It's essentially 
> similar to chunks, except the chunks themselves would not be of 
> the same length.
>
> You can think of a good name for '???' here. Maybe this is 
> already possible by combining functionality in std.range - but 
> I came up short.

You likely want to get involved / raise your support here:

https://github.com/dlang/phobos/pull/7600