How can I test at compile time whether T is an instance of an interface ?
otavio.porto at fatec.sp.gov.br
Thu Sep 24 00:33:08 UTC 2020
On Wednesday, 23 September 2020 at 18:37:45 UTC, wjoe wrote:
> I have some similar functions:
> void register(C: IFoo)()
> void register(C)() if (behavesLikeFoo!C)
> There are more overloads with parameters so I want to merge them
> void register(C, ARGS...)(ARGS args) if (behavesLikeFoo!C ||
> isInstanceOf!(C, IFoo))
> I found a lot of information on how to do this at runtime but
> not at compile time.
> std.traits: isInstanceOf doesn't work. Neither did anything I
> tried with typeid etc.
> The behavesLikeFoo constraint works as expected but it accepts
> any class no matter whether or not it implements the interface.
see if "import std.traits: isImplicitlyConvertible" helps you.
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