Unqualified class name
Jeremy T. Gibson
jtgibson at telus.net
Sat Aug 21 21:19:50 UTC 2021
On Saturday, 21 August 2021 at 18:45:07 UTC, jfondren wrote:
> On Saturday, 21 August 2021 at 17:33:51 UTC, Jeremy T. Gibson
> wrote:
>> is there a simple way to get the unqualified name of a class
>> at runtime without having to pass it through std.format?
>> `typeid(class).name` always yields the full classname,
>> including its module information (i.e.,
>> "modulename.classname"), where I only want "classname" on its
>> own.
>
> https://dlang.org/phobos/object.html#.TypeInfo_Class.name is
> all you have there, and it's just a string, so the simple way
> is to manipulate the string.
> string unqualified(string name) {
> import std.string : lastIndexOf;
> import std.algorithm : min;
>
> const i = name.lastIndexOf('.');
> return i == -1 ? name : name[min(i+1, $) .. $];
Parsing was always an option, but anytime I come across a
solution where parsing/formatting seems to be the answer, it
always feels more hacky than a genuine solution. Hacks can be
fine, especially in low-frequency code like the stuff I'm
revisiting this month, but I always prefer direct library-based
or language-based solutions whenever humanly possible. Dlang's
reference docs unfortunately assume a level of expertise with the
language (especially, expertise with code generation and compiler
specs) that makes it much harder for me to "ask the right
questions" when I'm searching: I'm really not much of a
programmer. Heh.
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