Can static variables in methods be local for each object?

[bauss]

On Tuesday, 20 July 2021 at 09:24:07 UTC, Mark Lagodych wrote:
> Let's say I have this code:
> ```d
> import std.stdio;
>
> class X {
>
>     int x(int param) {
>         static int myvar = 1234;
>
>         if (param == 0) return myvar;
>         else { myvar = param; return myvar; }
>     }
>
> }
>
> void main()
> {
>     X x1 = new X;
>     X x2 = new X;
>
>     x1.x(0).writeln;
>     x2.x(0).writeln;
>
>     x1.x(17).writeln;
>     x2.x(0).writeln;
> }
> ```
>
> Is there a way to make myvar local to each instance of `X` 
> without making it a variable of `X`? Just curious.

The only way I can think of is something like this:

```
import std.stdio;

interface X
{
     int x(int param);
}

class XImpl(size_t n = 0) : X {
     int x(int param) {
         static int myvar = 1234;

         if (param == 0) return myvar;
         else { myvar = param; return myvar; }
     }

}

void main()
{
     X x1 = new XImpl!1;
     X x2 = new XImpl!2;

     x1.x(0).writeln;
     x2.x(0).writeln;

     x1.x(17).writeln;
     x2.x(0).writeln;
}
```

Of course it's not entirely what you want but yeah I think that's 
about the closest to a solution that isn't overcomplicated.