Does is(f == function) work?

[Andrey Zherikov]

On Tuesday, 9 March 2021 at 18:53:06 UTC, Boris Carvajal wrote:
> On Tuesday, 9 March 2021 at 11:58:45 UTC, Andrey Zherikov wrote:
>> On Tuesday, 9 March 2021 at 02:57:46 UTC, Adam D. Ruppe wrote:
>>> try
>>>
>>> is(typeof(f) == function)
>>>
>>> it is kinda weird but that's the trick
>>
>> Thanks!
>> Should it work for in this case as well?
>>
>> alias f = (){};
>>
>> writeln(typeof(f).stringof);        // prints "void function() 
>> pure nothrow @nogc @safe"
>>
>> writeln(is(typeof(f) == function)); // prints "false"
>
> Not quite straightforward, but "void function()" is actually a 
> pointer to function, you need to dereference it first:
>
> is(typeof(*f) == function)

That's a trick! Thank you!