Passing a byLine as an argument to InputRange

[Ali Çehreli]

On 5/13/21 10:07 AM, Jeff wrote:

 > I have a class where I'd like to supply it with an InputRange!string.
 > Yet, for the life of me I can't seem to pass to it a File.byLine

As Adam said, your range elements need to be converted to string e.g. 
with 'text' (the same as to!string). However, you must also create a 
dynamic InputRange!string object for dynamic polymorphism that 
InputRange provides. And that's achieved by function inputRangeObject():

import std.range;
import std.stdio;
import std.algorithm;
import std.conv;

class Foo {
   private InputRange!string source;

   this(InputRange!string s) {
     source = s;
   }

   // do stuff with it
}

void main() {
   new Foo(inputRangeObject(File("stuff.txt").byLine.map!text));
}

Ali