Get UDAs of self's declaration as a member?

cc cc at nevernet.com
Mon Apr 25 21:32:16 UTC 2022


Hard to word this question right, but is it possible to get the 
UDAs assigned to a class/structure's member variable declaration, 
within that variable's definition?  e.g.

```d
import std.stdio;
import std.traits;
enum SPECIAL;
struct Foo {
	void foo() {
		static if (hasUDA!(typeof(this), SPECIAL))
			writeln("special");
		else
			writeln("not special");
	}
}
struct Bar {
	@SPECIAL Foo foo;
}

void main() {
	Foo foo;
	foo.foo;
	Bar bar;
	bar.foo.foo;
}
```

This doesn't work of course, `@SPECIAL` isn't applied to `struct 
Foo` itself so no UDA is found by `hasUDA!Foo`.  Without 
iterating Bar directly, is there some way to detect *within* 
Foo's member functions, that the Foo being called is declared 
with `@SPECIAL` inside its parent structure?


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