typeof(func!0) != typeof(func!0())

Andrey Zherikov andrey.zherikov at gmail.com
Mon Aug 22 14:43:24 UTC 2022

But the question is still opened: why is `typeof(U().func!0)` not 
the same as `typeof(U().func!0())`?

There is also inconsistency within UFCS - type depends on whether 
function is a member or standalone (even if I replace `auto ref` 
with `ref U`):
struct U
     ref U func(int i)() { return this; }
ref U func2(int i)(ref U u) { return u; }

void main()
     U u;
     pragma(msg, typeof(u.func!0));	// pure nothrow @nogc ref 
@safe U() return
     pragma(msg, typeof(u.func2!0));	// U

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